**Calculations**Rotary Indexer with Dial Plate Driving Application Torque Diagram |

**Step 1 : Moment of Inertia Calculations**- How to calculate the Moment of Inertia?
- Dial Plate Inertia, [I
_{d}] = 1/2 x 43.040 x ((1000/1000)/2)^2 = 5.380 Kg.m^{2}

Dial Plate Inertia |

- Stations Inertia, [I
_{st}] = 160 x ((450/1000)/2)^2 = 32.400 Kg.m^{2}

Stations Inertia |

- Additional Part Inertia, [I
_{add part}] = 8 x ((300/1000)/2)^2 = 0.720Kg.m ^{2}

Additional Parts Inertia |

- If there are others group of additional parts, do the same method.
- Total Moment of Inertia, [I
_{total}or ∑MK^{2}] = 5.380 + 32.400 + 0.720 = 38.500 Kg.m^{2}

Total Inertia |

- GD
^{2}= 38.500 x 4 x 9.81 = 1510.739 N.m^{2}

GD Square |

- Total Moving Mass, [∑M] = 43.040 + 120 + 8 = 211.040 Kg.

Total Moving Mass |

- Radius of Gyration, [K] = (I
_{total}/∑M)^1/2 = 427.118 mm

Radius of Gyration |

**Step 2 : Maximum Angular Acceleration Calculation**Cam Curve Characteristic Value |

- From the table, find the Dimensionless Maximum Angular Acceleration for Modified Sine Cam Curve, [A
_{m}] = 5.53 - Then, the Maximum Angular Acceleration, [a
_{m}] = 0.785 / 0.75^2 x 5.53 = 7.721 rad/sec^{2}

Maximum Angular Acceleration |

^{Step 3 : Required Torque Calculations}

Torque on Rotary Indexer |

- Inertia Torque at Index Shaft, [T
_{i}] = 38.500 x 7.721 = 297.271 N.m

- External Friction Torque to Indexer, [T
_{f}] = 10 N.m (Such as outboard support bearings, assume to 10 N.m) - Work Torque, [T
_{w}] = 0 N.m (Indexer is doing work such as lifting parts, assume to 0) - Total Output Torque, [T
_{t}] = 297.271 + 10 + 0 = 307.271 N.m

Total Torque at Output Shaft |

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