Rotary Indexer with Dial Plate Driving Application Torque Diagram |
Step 1 : Moment of Inertia Calculations
- How to calculate the Moment of Inertia?
- Dial Plate Inertia, [Id] = 1/2 x 43.040 x ((1000/1000)/2)^2 = 5.380 Kg.m2
Dial Plate Inertia |
- Stations Inertia, [Ist] = 160 x ((450/1000)/2)^2 = 32.400 Kg.m2
Stations Inertia |
- Additional Part Inertia, [Iadd part] = 8 x ((300/1000)/2)^2 = 0.720
Kg.m2
Additional Parts Inertia |
- If there are others group of additional parts, do the same method.
- Total Moment of Inertia, [Itotal or ∑MK2] = 5.380 + 32.400 + 0.720 = 38.500 Kg.m2
Total Inertia |
- GD2 = 38.500 x 4 x 9.81 = 1510.739 N.m2
GD Square |
- Total Moving Mass, [∑M] = 43.040 + 120 + 8 = 211.040 Kg.
Total Moving Mass |
- Radius of Gyration, [K] = (Itotal/∑M)^1/2 = 427.118 mm
Radius of Gyration |
Cam Curve Characteristic Value |
- From the table, find the Dimensionless Maximum Angular Acceleration for Modified Sine Cam Curve, [Am] = 5.53
- Then, the Maximum Angular Acceleration, [am] = 0.785 / 0.75^2 x 5.53 = 7.721 rad/sec2
Maximum Angular Acceleration |
Torque on Rotary Indexer |
- Inertia Torque at Index Shaft, [Ti] = 38.500 x 7.721 = 297.271 N.m
- External Friction Torque to Indexer, [Tf] = 10 N.m (Such as outboard support bearings, assume to 10 N.m)
- Work Torque, [Tw] = 0 N.m (Indexer is doing work such as lifting parts, assume to 0)
- Total Output Torque, [Tt] = 297.271 + 10 + 0 = 307.271 N.m
Total Torque at Output Shaft |
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